Submission #3420637

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Source Code Expand

#include <bits/stdc++.h>
using namespace std;

int main(){
  int N,M; cin >> N >> M;
  //max_i{min(N+i,M/2-i)}
  //N+i=M/2-i i=M/4-N/2
  double c=M/4.0-N/2.0;
  int i; if(c<0) i=0; else if(c>M/2.0) i=M/2; else i=floor(c);
  cout << max(min(N+i,M/2-i),min(N+i+1,M/2-i-1)) << endl;
}

Submission Info

Judge Result